131011142020032 has 112 divisors (see below), whose sum is σ = 352551860686080. Its totient is φ = 42924959766528.

The previous prime is 131011142019959. The next prime is 131011142020051. The reversal of 131011142020032 is 230020241110131.

131011142020032 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 131011142019990 and 131011142020008.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 92561053 + ... + 93965795.

Almost surely, 2^{131011142020032} is an apocalyptic number.

131011142020032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131011142020032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (176275930343040).

131011142020032 is an abundant number, since it is smaller than the sum of its proper divisors (221540718666048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131011142020032 is a wasteful number, since it uses less digits than its factorization.

131011142020032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1413050 (or 1413040 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 131011142020032 its reverse (230020241110131), we get a palindrome (361031383130163).

Subtracting 131011142020032 from its reverse (230020241110131), we obtain a palindrome (99009099090099).

The spelling of 131011142020032 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-two million, twenty thousand, thirty-two".