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13101123212173 is a prime number
BaseRepresentation
bin1011111010100101011111…
…0010111001001110001101
31201101110021210122221222001
42332221113302321032031
53204122100020242143
643510323425552301
72521345021621063
oct276512762711615
951343253587861
1013101123212173
1141a1178564817
1215771037a5691
1374057a0b5039
14334152308033
1517abcc2e014d
hexbea57cb938d

13101123212173 has 2 divisors, whose sum is σ = 13101123212174. Its totient is φ = 13101123212172.

The previous prime is 13101123212147. The next prime is 13101123212299. The reversal of 13101123212173 is 37121232110131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8134942161124 + 4966181051049 = 2852182^2 + 2228493^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13101123212173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13101123212773) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550561606086 + 6550561606087.

It is an arithmetic number, because the mean of its divisors is an integer number (6550561606087).

Almost surely, 213101123212173 is an apocalyptic number.

It is an amenable number.

13101123212173 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101123212173 is an equidigital number, since it uses as much as digits as its factorization.

13101123212173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 28.

The spelling of 13101123212173 in words is "thirteen trillion, one hundred one billion, one hundred twenty-three million, two hundred twelve thousand, one hundred seventy-three".