Base | Representation |
---|---|
bin | 11101110010011101111001… |
… | …001101110110010001100000 |
3 | 122011212120101012020212111002 |
4 | 131302131321031312101200 |
5 | 114132442342300300300 |
6 | 1142345452130211132 |
7 | 36411156101220461 |
oct | 3562357115662140 |
9 | 564776335225432 |
10 | 131011421103200 |
11 | 388206a482aa90 |
12 | 1283aa83a23aa8 |
13 | 5814429a98251 |
14 | 244cdb53b0d68 |
15 | 1022d938305d5 |
hex | 772779376460 |
131011421103200 has 576 divisors, whose sum is σ = 372457721180160. Its totient is φ = 44499456000000.
The previous prime is 131011421103193. The next prime is 131011421103209. The reversal of 131011421103200 is 2301124110131.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131011421103209) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4069799105 + ... + 4069831295.
It is an arithmetic number, because the mean of its divisors is an integer number (646627988160).
Almost surely, 2131011421103200 is an apocalyptic number.
131011421103200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131011421103200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (186228860590080).
131011421103200 is an abundant number, since it is smaller than the sum of its proper divisors (241446300076960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011421103200 is a wasteful number, since it uses less digits than its factorization.
131011421103200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32583 (or 32570 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 131011421103200 its reverse (2301124110131), we get a palindrome (133312545213331).
The spelling of 131011421103200 in words is "one hundred thirty-one trillion, eleven billion, four hundred twenty-one million, one hundred three thousand, two hundred".
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