Base | Representation |
---|---|
bin | 11101110010011101111010… |
… | …100001110011000011111100 |
3 | 122011212120102201122221022221 |
4 | 131302131322201303003330 |
5 | 114132442413414011030 |
6 | 1142345454234015124 |
7 | 36411156456245605 |
oct | 3562357241630374 |
9 | 564776381587287 |
10 | 131011443110140 |
11 | 388207061a113a |
12 | 1283aa8b2774a4 |
13 | 5814431501cc8 |
14 | 244cdb829cdac |
15 | 1022d9572ae7a |
hex | 77277a8730fc |
131011443110140 has 96 divisors (see below), whose sum is σ = 291329977075200. Its totient is φ = 49351288815360.
The previous prime is 131011443110117. The next prime is 131011443110209. The reversal of 131011443110140 is 41011344110131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 53716647 + ... + 56102593.
It is an arithmetic number, because the mean of its divisors is an integer number (3034687261200).
Almost surely, 2131011443110140 is an apocalyptic number.
131011443110140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131011443110140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (145664988537600).
131011443110140 is an abundant number, since it is smaller than the sum of its proper divisors (160318533965060).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011443110140 is a wasteful number, since it uses less digits than its factorization.
131011443110140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2386835 (or 2386833 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 131011443110140 its reverse (41011344110131), we get a palindrome (172022787220271).
Subtracting from 131011443110140 its reverse (41011344110131), we obtain a palindrome (90000099000009).
The spelling of 131011443110140 in words is "one hundred thirty-one trillion, eleven billion, four hundred forty-three million, one hundred ten thousand, one hundred forty".
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