Base | Representation |
---|---|
bin | 11101110010011110101001… |
… | …000010001001111001001000 |
3 | 122011212122110002210221020201 |
4 | 131302132221002021321020 |
5 | 114133001013134003300 |
6 | 1142350103505101544 |
7 | 36411215012156512 |
oct | 3562365102117110 |
9 | 564778402727221 |
10 | 131012223344200 |
11 | 38820a76661580 |
12 | 1283b0686278b4 |
13 | 5814527054173 |
14 | 244d04db60bb2 |
15 | 1022ddde9b66a |
hex | 7727a9089e48 |
131012223344200 has 48 divisors (see below), whose sum is σ = 332294639214960. Its totient is φ = 47640808488000.
The previous prime is 131012223344153. The next prime is 131012223344207. The reversal of 131012223344200 is 2443322210131.
It is not an unprimeable number, because it can be changed into a prime (131012223344207) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 29775503106 + ... + 29775507505.
It is an arithmetic number, because the mean of its divisors is an integer number (6922804983645).
Almost surely, 2131012223344200 is an apocalyptic number.
131012223344200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131012223344200 is an abundant number, since it is smaller than the sum of its proper divisors (201282415870760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131012223344200 is a wasteful number, since it uses less digits than its factorization.
131012223344200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59551010638 (or 59551010629 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 131012223344200 its reverse (2443322210131), we get a palindrome (133455545554331).
The spelling of 131012223344200 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-three million, three hundred forty-four thousand, two hundred".
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