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13101301221120 = 28355711175387
BaseRepresentation
bin1011111010100110001001…
…1001111100011100000000
31201101110202012121202100000
42332221202121330130000
53204122431103033440
643510353225200000
72521352312644440
oct276514231743400
951343665552300
1013101301221120
1141a1259a97552
121577153330000
137405a7c3c888
1433416bc04120
1517abdcc53730
hexbea6267c700

13101301221120 has 864 divisors, whose sum is σ = 53781500118528. Its totient is φ = 2991346827264.

The previous prime is 13101301221079. The next prime is 13101301221133. The reversal of 13101301221120 is 2112210310131.

13101301221120 is a `hidden beast` number, since 1 + 310 + 1 + 301 + 22 + 11 + 20 = 666.

It is a tau number, because it is divible by the number of its divisors (864).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13101301221093 and 13101301221102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2432019067 + ... + 2432024453.

Almost surely, 213101301221120 is an apocalyptic number.

13101301221120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13101301221120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26890750059264).

13101301221120 is an abundant number, since it is smaller than the sum of its proper divisors (40680198897408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13101301221120 is an equidigital number, since it uses as much as digits as its factorization.

13101301221120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6547 (or 6521 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 13101301221120 its reverse (2112210310131), we get a palindrome (15213511531251).

The spelling of 13101301221120 in words is "thirteen trillion, one hundred one billion, three hundred one million, two hundred twenty-one thousand, one hundred twenty".