1310131433440 has 24 divisors (see below), whose sum is σ = 3095185511880. Its totient is φ = 524052573312.

The previous prime is 1310131433437. The next prime is 1310131433447. The reversal of 1310131433440 is 443341310131.

It is a junction number, because it is equal to n+sod(n) for n = 1310131433399 and 1310131433408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310131433447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4094160570 + ... + 4094160889.

It is an arithmetic number, because the mean of its divisors is an integer number (128966062995).

Almost surely, 2^{1310131433440} is an apocalyptic number.

1310131433440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1310131433440 is an abundant number, since it is smaller than the sum of its proper divisors (1785054078440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310131433440 is an equidigital number, since it uses as much as digits as its factorization.

1310131433440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8188321474 (or 8188321466 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1310131433440 its reverse (443341310131), we get a palindrome (1753472743571).

The spelling of 1310131433440 in words is "one trillion, three hundred ten billion, one hundred thirty-one million, four hundred thirty-three thousand, four hundred forty".