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13102013 is a prime number
BaseRepresentation
bin110001111110…
…101110111101
3220122122120202
4301332232331
511323231023
61144453245
7216236201
oct61765675
926578522
1013102013
117439811
12447a225
132939792
141a50b01
15123c128
hexc7ebbd

13102013 has 2 divisors, whose sum is σ = 13102014. Its totient is φ = 13102012.

The previous prime is 13102009. The next prime is 13102021. The reversal of 13102013 is 31020131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12694969 + 407044 = 3563^2 + 638^2 .

It is a cyclic number.

It is not a de Polignac number, because 13102013 - 22 = 13102009 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13101985 and 13102003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13102003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6551006 + 6551007.

It is an arithmetic number, because the mean of its divisors is an integer number (6551007).

Almost surely, 213102013 is an apocalyptic number.

It is an amenable number.

13102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13102013 is an equidigital number, since it uses as much as digits as its factorization.

13102013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 13102013 is about 3619.6702888523. The cubic root of 13102013 is about 235.7469098051.

Adding to 13102013 its reverse (31020131), we get a palindrome (44122144).

The spelling of 13102013 in words is "thirteen million, one hundred two thousand, thirteen".