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1310202012143 = 3533711620431
BaseRepresentation
bin10011000100001110001…
…000000010000111101111
311122020212020020100220202
4103010032020002013233
5132431243203342033
62441522024104115
7163442012231123
oct23041610020757
94566766210822
101310202012143
11465720973992
12191b1400503b
13967228c4a0b
14475b2495583
15241348d88e8
hex1310e2021ef

1310202012143 has 4 divisors (see below), whose sum is σ = 1313913632928. Its totient is φ = 1306490391360.

The previous prime is 1310202012127. The next prime is 1310202012167. The reversal of 1310202012143 is 3412102020131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1310202012143 - 24 = 1310202012127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310202012173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1855809863 + ... + 1855810568.

It is an arithmetic number, because the mean of its divisors is an integer number (328478408232).

Almost surely, 21310202012143 is an apocalyptic number.

1310202012143 is a deficient number, since it is larger than the sum of its proper divisors (3711620785).

1310202012143 is an equidigital number, since it uses as much as digits as its factorization.

1310202012143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3711620784.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1310202012143 its reverse (3412102020131), we get a palindrome (4722304032274).

The spelling of 1310202012143 in words is "one trillion, three hundred ten billion, two hundred two million, twelve thousand, one hundred forty-three".

Divisors: 1 353 3711620431 1310202012143