131020241113140 has 96 divisors (see below), whose sum is σ = 369012388832640. Its totient is φ = 34733463384576.

The previous prime is 131020241113057. The next prime is 131020241113183. The reversal of 131020241113140 is 41311142020131.

It is a super-2 number, since 2×131020241113140² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131020241113140.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 109317807 + ... + 110509833.

It is an arithmetic number, because the mean of its divisors is an integer number (3843879050340).

Almost surely, 2^{131020241113140} is an apocalyptic number.

131020241113140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131020241113140 is an abundant number, since it is smaller than the sum of its proper divisors (237992147719500).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131020241113140 is a wasteful number, since it uses less digits than its factorization.

131020241113140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1202801 (or 1202799 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 131020241113140 its reverse (41311142020131), we get a palindrome (172331383133271).

The spelling of 131020241113140 in words is "one hundred thirty-one trillion, twenty billion, two hundred forty-one million, one hundred thirteen thousand, one hundred forty".