131020241142311 has 2 divisors, whose sum is σ = 131020241142312. Its totient is φ = 131020241142310.

The previous prime is 131020241142293. The next prime is 131020241142313. The reversal of 131020241142311 is 113241142020131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131020241142311 is a prime.

Together with 131020241142313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131020241142313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510120571155 + 65510120571156.

It is an arithmetic number, because the mean of its divisors is an integer number (65510120571156).

Almost surely, 2^{131020241142311} is an apocalyptic number.

131020241142311 is a deficient number, since it is larger than the sum of its proper divisors (1).

131020241142311 is an equidigital number, since it uses as much as digits as its factorization.

131020241142311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 131020241142311 its reverse (113241142020131), we get a palindrome (244261383162442).

The spelling of 131020241142311 in words is "one hundred thirty-one trillion, twenty billion, two hundred forty-one million, one hundred forty-two thousand, three hundred eleven".