131020442141 has 2 divisors, whose sum is σ = 131020442142. Its totient is φ = 131020442140.

The previous prime is 131020442131. The next prime is 131020442143. The reversal of 131020442141 is 141244020131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90633510916 + 40386931225 = 301054^2 + 200965^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131020442141 is a prime.

Together with 131020442143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131020442143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65510221070 + 65510221071.

It is an arithmetic number, because the mean of its divisors is an integer number (65510221071).

Almost surely, 2^131020442141 is an apocalyptic number.

It is an amenable number.

131020442141 is a deficient number, since it is larger than the sum of its proper divisors (1).

131020442141 is an equidigital number, since it uses as much as digits as its factorization.

131020442141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 131020442141 its reverse (141244020131), we get a palindrome (272264462272).

The spelling of 131020442141 in words is "one hundred thirty-one billion, twenty million, four hundred forty-two thousand, one hundred forty-one".