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131021010111420 = 2232511133175917123
BaseRepresentation
bin11101110010100110110100…
…110001000000101110111100
3122011220111010110122221212200
4131302212310301000232330
5114133122012042031140
61142354115432031500
736411645525360612
oct3562466461005674
9564814113587780
10131021010111420
1138824775551870
12128408bb232590
1358152c7596000
14244d644b0b6b2
1510232555a8030
hex7729b4c40bbc

131021010111420 has 576 divisors, whose sum is σ = 469968481382400. Its totient is φ = 29301007357440.

The previous prime is 131021010111389. The next prime is 131021010111457. The reversal of 131021010111420 is 24111010120131.

131021010111420 is a `hidden beast` number, since 1 + 3 + 10 + 210 + 10 + 1 + 11 + 420 = 666.

It is a super-4 number, since 4×1310210101114204 (a number of 58 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 131021010111393 and 131021010111402.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 7651746979 + ... + 7651764101.

It is an arithmetic number, because the mean of its divisors is an integer number (815917502400).

Almost surely, 2131021010111420 is an apocalyptic number.

131021010111420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131021010111420, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (234984240691200).

131021010111420 is an abundant number, since it is smaller than the sum of its proper divisors (338947471270980).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131021010111420 is a wasteful number, since it uses less digits than its factorization.

131021010111420 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18947 (or 18916 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 18.

Adding to 131021010111420 its reverse (24111010120131), we get a palindrome (155132020231551).

The spelling of 131021010111420 in words is "one hundred thirty-one trillion, twenty-one billion, ten million, one hundred eleven thousand, four hundred twenty".