Base | Representation |
---|---|
bin | 1011111010101001001011… |
… | …0011001000011011011000 |
3 | 1201101112211210101000012200 |
4 | 2332222102303020123120 |
5 | 3204131111430131300 |
6 | 43511005551210200 |
7 | 2521411402031343 |
oct | 276522263103330 |
9 | 51345753330180 |
10 | 13102113130200 |
11 | 41a1636321896 |
12 | 157733b216960 |
13 | 7406a7202253 |
14 | 33420798d45a |
15 | 17ac3917e200 |
hex | bea92cc86d8 |
13102113130200 has 144 divisors (see below), whose sum is σ = 44023851378000. Its totient is φ = 3492103238400.
The previous prime is 13102113130193. The next prime is 13102113130201. The reversal of 13102113130200 is 203131120131.
13102113130200 is a `hidden beast` number, since 1 + 310 + 21 + 1 + 3 + 130 + 200 = 666.
13102113130200 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13102113130201) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 1640845 + ... + 5375555.
It is an arithmetic number, because the mean of its divisors is an integer number (305721190125).
Almost surely, 213102113130200 is an apocalyptic number.
13102113130200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13102113130200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22011925689000).
13102113130200 is an abundant number, since it is smaller than the sum of its proper divisors (30921738247800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102113130200 is a wasteful number, since it uses less digits than its factorization.
13102113130200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3736682 (or 3736670 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 13102113130200 its reverse (203131120131), we get a palindrome (13305244250331).
The spelling of 13102113130200 in words is "thirteen trillion, one hundred two billion, one hundred thirteen million, one hundred thirty thousand, two hundred".
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