Base | Representation |
---|---|
bin | 11101110010100110111100… |
… | …101100010100101111111010 |
3 | 122011220111110201220111110211 |
4 | 131302212330230110233322 |
5 | 114133122300113203120 |
6 | 1142354140542301334 |
7 | 36411652031640613 |
oct | 3562467454245772 |
9 | 564814421814424 |
10 | 131021143100410 |
11 | 38824833625422 |
12 | 1284093788784a |
13 | 5815318cba114 |
14 | 244d658648c0a |
15 | 10232620c725a |
hex | 7729bcb14bfa |
131021143100410 has 64 divisors (see below), whose sum is σ = 261991748312064. Its totient is φ = 46951925990400.
The previous prime is 131021143100401. The next prime is 131021143100417. The reversal of 131021143100410 is 14001341120131.
It is a super-2 number, since 2×1310211431004102 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131021143100417) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 203462932 + ... + 204105871.
It is an arithmetic number, because the mean of its divisors is an integer number (4093621067376).
Almost surely, 2131021143100410 is an apocalyptic number.
131021143100410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131021143100410 is a deficient number, since it is larger than the sum of its proper divisors (130970605211654).
131021143100410 is a wasteful number, since it uses less digits than its factorization.
131021143100410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 407568919.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 131021143100410 its reverse (14001341120131), we get a palindrome (145022484220541).
The spelling of 131021143100410 in words is "one hundred thirty-one trillion, twenty-one billion, one hundred forty-three million, one hundred thousand, four hundred ten".
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