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131021423120000 = 275473143175519
BaseRepresentation
bin11101110010100111001101…
…011000100000111010000000
3122011220112012020210222010202
4131302213031120200322000
5114133123333304320000
61142354224424144332
736411662002032350
oct3562471530407200
9564815166728122
10131021423120000
11388249676a2276
12128409b56080a8
13581536201069a
14244d6838dab60
15102327b98add5
hex7729cd620e80

131021423120000 has 640 divisors, whose sum is σ = 393740842598400. Its totient is φ = 42461314560000.

The previous prime is 131021423119943. The next prime is 131021423120011. The reversal of 131021423120000 is 21324120131.

It is a tau number, because it is divible by the number of its divisors (640).

It is a super-2 number, since 2×1310214231200002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 746392241 + ... + 746567759.

It is an arithmetic number, because the mean of its divisors is an integer number (615220066560).

Almost surely, 2131021423120000 is an apocalyptic number.

131021423120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131021423120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (196870421299200).

131021423120000 is an abundant number, since it is smaller than the sum of its proper divisors (262719419478400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131021423120000 is an equidigital number, since it uses as much as digits as its factorization.

131021423120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175634 (or 175607 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 131021423120000 its reverse (21324120131), we get a palindrome (131042747240131).

The spelling of 131021423120000 in words is "one hundred thirty-one trillion, twenty-one billion, four hundred twenty-three million, one hundred twenty thousand".