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131022001411000 = 23537234119848811
BaseRepresentation
bin11101110010100111101111…
…110110100001001110111000
3122011220120200112222012020221
4131302213233312201032320
5114133131024330123000
61142354402043025424
736412012223314060
oct3562475766411670
9564816615865227
10131022001411000
1138825134072917
1212840b3720b274
135815424a77ccb
14244d6da6323a0
1510232b261b61a
hex7729efda13b8

131022001411000 has 256 divisors, whose sum is σ = 374542318725120. Its totient is φ = 41920686720000.

The previous prime is 131022001410947. The next prime is 131022001411003. The reversal of 131022001411000 is 114100220131.

It is a super-4 number, since 4×1310220014110004 (a number of 58 digits) contains 4444 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131022001411003) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3323406 + ... + 16525405.

It is an arithmetic number, because the mean of its divisors is an integer number (1463055932520).

Almost surely, 2131022001411000 is an apocalyptic number.

131022001411000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131022001411000 is an abundant number, since it is smaller than the sum of its proper divisors (243520317314120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131022001411000 is a wasteful number, since it uses less digits than its factorization.

131022001411000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19848903 (or 19848889 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 131022001411000 its reverse (114100220131), we get a palindrome (131136101631131).

The spelling of 131022001411000 in words is "one hundred thirty-one trillion, twenty-two billion, one million, four hundred eleven thousand".