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131023131112 = 2316377891389
BaseRepresentation
bin111101000000110010…
…1100101000111101000
3110112012020010200122201
41322001211211013220
54121313410143422
6140105144225544
712315606144616
oct1720145450750
9415166120581
10131023131112
1150626161735
122148746b2b4
13c480b50363
1464ad3186b6
15361cab3727
hex1e819651e8

131023131112 has 8 divisors (see below), whose sum is σ = 245668370850. Its totient is φ = 65511565552.

The previous prime is 131023131089. The next prime is 131023131137. The reversal of 131023131112 is 211131320131.

It can be written as a sum of positive squares in only one way, i.e., 129207178116 + 1815952996 = 359454^2 + 42614^2 .

It is a tau number, because it is divible by the number of its divisors (8).

It is a self number, because there is not a number n which added to its sum of digits gives 131023131112.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8188945687 + ... + 8188945702.

Almost surely, 2131023131112 is an apocalyptic number.

It is an amenable number.

131023131112 is a deficient number, since it is larger than the sum of its proper divisors (114645239738).

131023131112 is a wasteful number, since it uses less digits than its factorization.

131023131112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16377891395 (or 16377891391 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 131023131112 its reverse (211131320131), we get a palindrome (342154451243).

The spelling of 131023131112 in words is "one hundred thirty-one billion, twenty-three million, one hundred thirty-one thousand, one hundred twelve".

Divisors: 1 2 4 8 16377891389 32755782778 65511565556 131023131112