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1310240114 = 21921814737
BaseRepresentation
bin100111000011000…
…1010110101110010
310101022110002112122
41032012022311302
510140410140424
6334002554242
744316600011
oct11606126562
93338402478
101310240114
11612661877
12306968982
1317b5b1c11
14c6028a78
157a06445e
hex4e18ad72

1310240114 has 12 divisors (see below), whose sum is σ = 2074245534. Its totient is φ = 620639712.

The previous prime is 1310240101. The next prime is 1310240119. The reversal of 1310240114 is 4110420131.

It is a happy number.

It can be written as a sum of positive squares in only one way, i.e., 906913225 + 403326889 = 30115^2 + 20083^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1310240092 and 1310240101.

It is not an unprimeable number, because it can be changed into a prime (1310240119) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 906647 + ... + 908090.

Almost surely, 21310240114 is an apocalyptic number.

1310240114 is a deficient number, since it is larger than the sum of its proper divisors (764005420).

1310240114 is a wasteful number, since it uses less digits than its factorization.

1310240114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1814777 (or 1814758 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1310240114 is about 36197.2390383576. The cubic root of 1310240114 is about 1094.2510294271.

Adding to 1310240114 its reverse (4110420131), we get a palindrome (5420660245).

The spelling of 1310240114 in words is "one billion, three hundred ten million, two hundred forty thousand, one hundred fourteen".

Divisors: 1 2 19 38 361 722 1814737 3629474 34480003 68960006 655120057 1310240114