Base | Representation |
---|---|
bin | 11101110010101001101001… |
… | …011000101100101101011000 |
3 | 122011220202221122201021121001 |
4 | 131302221221120230231120 |
5 | 114133144213321222130 |
6 | 1142355340241554344 |
7 | 36412113602462254 |
oct | 3562515130545530 |
9 | 564822848637531 |
10 | 131024040414040 |
11 | 38825a90029aa4 |
12 | 128414060459b4 |
13 | 581568b32a197 |
14 | 244d851361264 |
15 | 10233816356ca |
hex | 772a6962cb58 |
131024040414040 has 64 divisors (see below), whose sum is σ = 304748016318720. Its totient is φ = 50646630720000.
The previous prime is 131024040413999. The next prime is 131024040414077. The reversal of 131024040414040 is 40414040420131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 74497771 + ... + 76236250.
It is an arithmetic number, because the mean of its divisors is an integer number (4761687754980).
Almost surely, 2131024040414040 is an apocalyptic number.
131024040414040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131024040414040 is an abundant number, since it is smaller than the sum of its proper divisors (173723975904680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131024040414040 is a wasteful number, since it uses less digits than its factorization.
131024040414040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 150734764 (or 150734760 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 131024040414040 its reverse (40414040420131), we get a palindrome (171438080834171).
The spelling of 131024040414040 in words is "one hundred thirty-one trillion, twenty-four billion, forty million, four hundred fourteen thousand, forty".
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