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13102433 = 23569671
BaseRepresentation
bin110001111110…
…110101100001
3220122200011022
4301332311201
511323234213
61144455225
7216240341
oct61766541
926580138
1013102433
11743a063
12447a515
132939a26
141a50d21
15123c308
hexc7ed61

13102433 has 4 divisors (see below), whose sum is σ = 13672128. Its totient is φ = 12532740.

The previous prime is 13102417. The next prime is 13102459. The reversal of 13102433 is 33420131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33420131 = 61547871.

It is a cyclic number.

It is not a de Polignac number, because 13102433 - 24 = 13102417 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13102483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 284813 + ... + 284858.

It is an arithmetic number, because the mean of its divisors is an integer number (3418032).

Almost surely, 213102433 is an apocalyptic number.

It is an amenable number.

13102433 is a deficient number, since it is larger than the sum of its proper divisors (569695).

13102433 is an equidigital number, since it uses as much as digits as its factorization.

13102433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 569694.

The product of its (nonzero) digits is 216, while the sum is 17.

The square root of 13102433 is about 3619.7283047212. The cubic root of 13102433 is about 235.7494288238.

Adding to 13102433 its reverse (33420131), we get a palindrome (46522564).

The spelling of 13102433 in words is "thirteen million, one hundred two thousand, four hundred thirty-three".

Divisors: 1 23 569671 13102433