Base | Representation |
---|---|
bin | 1011111010101010010111… |
… | …1001001111110010111000 |
3 | 1201101120200010012111102120 |
4 | 2332222211321033302320 |
5 | 3204132240434002334 |
6 | 43511101434001240 |
7 | 2521422342111156 |
oct | 276524571176270 |
9 | 51346603174376 |
10 | 13102433500344 |
11 | 41a1790149701 |
12 | 157740a576220 |
13 | 7407286b2a96 |
14 | 3342383463d6 |
15 | 17ac57363949 |
hex | beaa5e4fcb8 |
13102433500344 has 128 divisors (see below), whose sum is σ = 35672150304000. Its totient is φ = 3994587878400.
The previous prime is 13102433500339. The next prime is 13102433500361. The reversal of 13102433500344 is 44300533420131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 181410399 + ... + 181482609.
It is an arithmetic number, because the mean of its divisors is an integer number (278688674250).
Almost surely, 213102433500344 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13102433500344, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17836075152000).
13102433500344 is an abundant number, since it is smaller than the sum of its proper divisors (22569716803656).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102433500344 is a wasteful number, since it uses less digits than its factorization.
13102433500344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85989 (or 85985 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 13102433500344 its reverse (44300533420131), we get a palindrome (57402966920475).
The spelling of 13102433500344 in words is "thirteen trillion, one hundred two billion, four hundred thirty-three million, five hundred thousand, three hundred forty-four".
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