Base | Representation |
---|---|
bin | 111101000000110111… |
… | …0110001111111011111 |
3 | 110112012101200020022220 |
4 | 1322001232301333133 |
5 | 4121320014340020 |
6 | 140105312040423 |
7 | 12315635512014 |
oct | 1720156617737 |
9 | 415171606286 |
10 | 131025543135 |
11 | 50627559943 |
12 | 21488233113 |
13 | c4814b61a6 |
14 | 64ad78570b |
15 | 361cddd240 |
hex | 1e81bb1fdf |
131025543135 has 32 divisors (see below), whose sum is σ = 221836796928. Its totient is φ = 65900567040.
The previous prime is 131025543101. The next prime is 131025543139. The reversal of 131025543135 is 531345520131.
It is not a de Polignac number, because 131025543135 - 212 = 131025539039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131025543096 and 131025543105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131025543139) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2650042 + ... + 2699031.
It is an arithmetic number, because the mean of its divisors is an integer number (6932399904).
Almost surely, 2131025543135 is an apocalyptic number.
131025543135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131025543135 is a deficient number, since it is larger than the sum of its proper divisors (90811253793).
131025543135 is a wasteful number, since it uses less digits than its factorization.
131025543135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5349175.
The product of its (nonzero) digits is 27000, while the sum is 33.
The spelling of 131025543135 in words is "one hundred thirty-one billion, twenty-five million, five hundred forty-three thousand, one hundred thirty-five".
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