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1310302020021 = 31725692196471
BaseRepresentation
bin10011000100010100000…
…101100010000110110101
311122021010012102021221020
4103010110011202012311
5132431444304120041
62441535555411353
7163444335255231
oct23042405420665
94567105367836
101310302020021
11465772370325
12191b415b3b59
139673a53bc87
14475c18895c1
152413d590866
hex131141621b5

1310302020021 has 8 divisors (see below), whose sum is σ = 1849838145984. Its totient is φ = 822150287040.

The previous prime is 1310302019993. The next prime is 1310302020037. The reversal of 1310302020021 is 1200202030131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1310302020021 - 222 = 1310297825717 is a prime.

It is a super-2 number, since 2×13103020200212 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310302020121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12846098185 + ... + 12846098286.

It is an arithmetic number, because the mean of its divisors is an integer number (231229768248).

Almost surely, 21310302020021 is an apocalyptic number.

It is an amenable number.

1310302020021 is a deficient number, since it is larger than the sum of its proper divisors (539536125963).

1310302020021 is a wasteful number, since it uses less digits than its factorization.

1310302020021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25692196491.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 1310302020021 its reverse (1200202030131), we get a palindrome (2510504050152).

The spelling of 1310302020021 in words is "one trillion, three hundred ten billion, three hundred two million, twenty thousand, twenty-one".

Divisors: 1 3 17 51 25692196471 77076589413 436767340007 1310302020021