Base | Representation |
---|---|
bin | 11101110010110000001110… |
… | …001111001101000011011111 |
3 | 122011221110011201200222011112 |
4 | 131302300032033031003133 |
5 | 114133303143342224043 |
6 | 1142402505025412235 |
7 | 36412453556551640 |
oct | 3562601617150337 |
9 | 564843151628145 |
10 | 131031101133023 |
11 | 38828a83685743 |
12 | 1284285679a07b |
13 | 58162450a2400 |
14 | 244dd20da56c7 |
15 | 1023646445518 |
hex | 772c0e3cd0df |
131031101133023 has 12 divisors (see below), whose sum is σ = 162155141217648. Its totient is φ = 103672959137280.
The previous prime is 131031101132993. The next prime is 131031101133109. The reversal of 131031101133023 is 320331101130131.
It is not a de Polignac number, because 131031101133023 - 222 = 131031096938719 is a prime.
It is a super-2 number, since 2×1310311011330232 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 131031101133023.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131031101183023) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 55380853058 + ... + 55380855423.
It is an arithmetic number, because the mean of its divisors is an integer number (13512928434804).
Almost surely, 2131031101133023 is an apocalyptic number.
131031101133023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
131031101133023 is a deficient number, since it is larger than the sum of its proper divisors (31124040084625).
131031101133023 is a wasteful number, since it uses less digits than its factorization.
131031101133023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110761708514 (or 110761708501 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 131031101133023 its reverse (320331101130131), we get a palindrome (451362202263154).
The spelling of 131031101133023 in words is "one hundred thirty-one trillion, thirty-one billion, one hundred one million, one hundred thirty-three thousand, twenty-three".
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