13103114020 has 96 divisors (see below), whose sum is σ = 29663262720. Its totient is φ = 4846250880.

The previous prime is 13103113999. The next prime is 13103114033. The reversal of 13103114020 is 2041130131.

It is a super-2 number, since 2×13103114020² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13103113985 and 13103114003.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8339835 + ... + 8341405.

It is an arithmetic number, because the mean of its divisors is an integer number (308992320).

Almost surely, 2^13103114020 is an apocalyptic number.

13103114020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13103114020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14831631360).

13103114020 is an abundant number, since it is smaller than the sum of its proper divisors (16560148700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13103114020 is a wasteful number, since it uses less digits than its factorization.

13103114020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2113 (or 2111 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13103114020 its reverse (2041130131), we get a palindrome (15144244151).

The spelling of 13103114020 in words is "thirteen billion, one hundred three million, one hundred fourteen thousand, twenty".