Base | Representation |
---|---|
bin | 11101110010110000010101… |
… | …100000100000111010000101 |
3 | 122011221110111020020002220112 |
4 | 131302300111200200322011 |
5 | 114133303421104030201 |
6 | 1142402525104042405 |
7 | 36412456600422512 |
oct | 3562602540407205 |
9 | 564843436202815 |
10 | 131031223111301 |
11 | 38829036518837 |
12 | 1284288b603405 |
13 | 581626443c8c6 |
14 | 244dd33278309 |
15 | 1023651edc0bb |
hex | 772c15820e85 |
131031223111301 has 2 divisors, whose sum is σ = 131031223111302. Its totient is φ = 131031223111300.
The previous prime is 131031223111267. The next prime is 131031223111363. The reversal of 131031223111301 is 103111322130131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 91424213683201 + 39607009428100 = 9561601^2 + 6293410^2 .
It is a cyclic number.
It is not a de Polignac number, because 131031223111301 - 26 = 131031223111237 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131031223111501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65515611555650 + 65515611555651.
It is an arithmetic number, because the mean of its divisors is an integer number (65515611555651).
Almost surely, 2131031223111301 is an apocalyptic number.
It is an amenable number.
131031223111301 is a deficient number, since it is larger than the sum of its proper divisors (1).
131031223111301 is an equidigital number, since it uses as much as digits as its factorization.
131031223111301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 131031223111301 its reverse (103111322130131), we get a palindrome (234142545241432).
The spelling of 131031223111301 in words is "one hundred thirty-one trillion, thirty-one billion, two hundred twenty-three million, one hundred eleven thousand, three hundred one".
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