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131034112000 = 213531111633
BaseRepresentation
bin111101000001000111…
…1011110000000000000
3110112012222210120121021
41322002033132000000
54121324213041000
6140110215435224
712316101401101
oct1720217360000
9415188716537
10131034112000
1150631381850
122148b085b14
13c4831c651c
1464b09763a8
15361da3211a
hex1e823de000

131034112000 has 224 divisors, whose sum is σ = 356802866784. Its totient is φ = 47644672000.

The previous prime is 131034111953. The next prime is 131034112021. The reversal of 131034112000 is 211430131.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11258184 + ... + 11269816.

It is an arithmetic number, because the mean of its divisors is an integer number (1592869941).

Almost surely, 2131034112000 is an apocalyptic number.

131034112000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131034112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (178401433392).

131034112000 is an abundant number, since it is smaller than the sum of its proper divisors (225768754784).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131034112000 is an equidigital number, since it uses as much as digits as its factorization.

131034112000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11685 (or 11651 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 131034112000 its reverse (211430131), we get a palindrome (131245542131).

The spelling of 131034112000 in words is "one hundred thirty-one billion, thirty-four million, one hundred twelve thousand".