Base | Representation |
---|---|
bin | 10011000100010111000… |
… | …110000110111010101000 |
3 | 11122021020201102001210110 |
4 | 103010113012012322220 |
5 | 132432100220034230 |
6 | 2441545001414320 |
7 | 163445520332262 |
oct | 23042706067250 |
9 | 4567221361713 |
10 | 1310352502440 |
11 | 465798910533 |
12 | 191b5649a3a0 |
13 | 96747b35b27 |
14 | 475c846ab32 |
15 | 24142c134b0 |
hex | 13117186ea8 |
1310352502440 has 64 divisors (see below), whose sum is σ = 3984907636800. Its totient is φ = 344640655872.
The previous prime is 1310352502399. The next prime is 1310352502447. The reversal of 1310352502440 is 442052530131.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 1310352502398 and 1310352502407.
It is not an unprimeable number, because it can be changed into a prime (1310352502447) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 74783050 + ... + 74800569.
It is an arithmetic number, because the mean of its divisors is an integer number (62264181825).
Almost surely, 21310352502440 is an apocalyptic number.
1310352502440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1310352502440 is an abundant number, since it is smaller than the sum of its proper divisors (2674555134360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310352502440 is a wasteful number, since it uses less digits than its factorization.
1310352502440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 149583706 (or 149583702 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
The spelling of 1310352502440 in words is "one trillion, three hundred ten billion, three hundred fifty-two million, five hundred two thousand, four hundred forty".
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