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131040134341 is a prime number
BaseRepresentation
bin111101000001010011…
…0011100010011000101
3110112020102010112200221
41322002212130103011
54121332233244331
6140110552504341
712316203522664
oct1720246342305
9415212115627
10131040134341
1150634815496
12214910ab0b1
13c48452473c
1464b16a2ddb
15361e321711
hex1e8299c4c5

131040134341 has 2 divisors, whose sum is σ = 131040134342. Its totient is φ = 131040134340.

The previous prime is 131040134333. The next prime is 131040134353. The reversal of 131040134341 is 143431040131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94805489025 + 36234645316 = 307905^2 + 190354^2 .

It is a cyclic number.

It is not a de Polignac number, because 131040134341 - 23 = 131040134333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131040134311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65520067170 + 65520067171.

It is an arithmetic number, because the mean of its divisors is an integer number (65520067171).

Almost surely, 2131040134341 is an apocalyptic number.

It is an amenable number.

131040134341 is a deficient number, since it is larger than the sum of its proper divisors (1).

131040134341 is an equidigital number, since it uses as much as digits as its factorization.

131040134341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131040134341 its reverse (143431040131), we get a palindrome (274471174472).

The spelling of 131040134341 in words is "one hundred thirty-one billion, forty million, one hundred thirty-four thousand, three hundred forty-one".