Base | Representation |
---|---|
bin | 10011000100011010000… |
… | …000101110001011000111 |
3 | 11122021101010110102211212 |
4 | 103010122000232023013 |
5 | 132432200231001043 |
6 | 2441553510122035 |
7 | 163446653210051 |
oct | 23043200561307 |
9 | 4567333412755 |
10 | 1310401422023 |
11 | 465813493541 |
12 | 191b6a95031b |
13 | 96755003525 |
14 | 475d0b628d1 |
15 | 24147178018 |
hex | 1311a02e2c7 |
1310401422023 has 2 divisors, whose sum is σ = 1310401422024. Its totient is φ = 1310401422022.
The previous prime is 1310401422017. The next prime is 1310401422091. The reversal of 1310401422023 is 3202241040131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310401422023 - 24 = 1310401422007 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1310401422023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1310401422923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655200711011 + 655200711012.
It is an arithmetic number, because the mean of its divisors is an integer number (655200711012).
Almost surely, 21310401422023 is an apocalyptic number.
1310401422023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310401422023 is an equidigital number, since it uses as much as digits as its factorization.
1310401422023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1310401422023 its reverse (3202241040131), we get a palindrome (4512642462154).
The spelling of 1310401422023 in words is "one trillion, three hundred ten billion, four hundred one million, four hundred twenty-two thousand, twenty-three".
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