Search a number
-
+
1310402113 is a prime number
BaseRepresentation
bin100111000011011…
…0010011001000001
310101022202022202121
41032012302121001
510140430331423
6334010244241
744321143216
oct11606623101
93338668677
101310402113
11612762559
12306a26681
1317b63a887
14c606bb0d
157a09745d
hex4e1b2641

1310402113 has 2 divisors, whose sum is σ = 1310402114. Its totient is φ = 1310402112.

The previous prime is 1310402111. The next prime is 1310402141. The reversal of 1310402113 is 3112040131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1223390529 + 87011584 = 34977^2 + 9328^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310402113 - 21 = 1310402111 is a prime.

Together with 1310402111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1310402111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655201056 + 655201057.

It is an arithmetic number, because the mean of its divisors is an integer number (655201057).

Almost surely, 21310402113 is an apocalyptic number.

It is an amenable number.

1310402113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310402113 is an equidigital number, since it uses as much as digits as its factorization.

1310402113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1310402113 is about 36199.4766951126. The cubic root of 1310402113 is about 1094.2961255550.

Adding to 1310402113 its reverse (3112040131), we get a palindrome (4422442244).

The spelling of 1310402113 in words is "one billion, three hundred ten million, four hundred two thousand, one hundred thirteen".