13104040134103 has 2 divisors, whose sum is σ = 13104040134104. Its totient is φ = 13104040134102.

The previous prime is 13104040134083. The next prime is 13104040134109. The reversal of 13104040134103 is 30143104040131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13104040134103 is a prime.

It is a super-2 number, since 2×13104040134103² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104040134109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552020067051 + 6552020067052.

It is an arithmetic number, because the mean of its divisors is an integer number (6552020067052).

Almost surely, 2^{13104040134103} is an apocalyptic number.

13104040134103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104040134103 is an equidigital number, since it uses as much as digits as its factorization.

13104040134103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13104040134103 its reverse (30143104040131), we get a palindrome (43247144174234).

The spelling of 13104040134103 in words is "thirteen trillion, one hundred four billion, forty million, one hundred thirty-four thousand, one hundred three".