Base | Representation |
---|---|
bin | 1011111010110000010111… |
… | …0010011010001000111000 |
3 | 1201101201211020111000201001 |
4 | 2332230011302122020320 |
5 | 3204144034313223230 |
6 | 43511525224334344 |
7 | 2521510245624601 |
oct | 276540562321070 |
9 | 51351736430631 |
10 | 13104042320440 |
11 | 41a24362a4a95 |
12 | 15777993143b4 |
13 | 740923ab6336 |
14 | 33434bc94da8 |
15 | 17aced7060ca |
hex | beb05c9a238 |
13104042320440 has 32 divisors (see below), whose sum is σ = 29499887620080. Its totient is φ = 5238809390592.
The previous prime is 13104042320429. The next prime is 13104042320443. The reversal of 13104042320440 is 4402324040131.
It is a junction number, because it is equal to n+sod(n) for n = 13104042320399 and 13104042320408.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104042320443) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 87659937 + ... + 87809296.
Almost surely, 213104042320440 is an apocalyptic number.
13104042320440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13104042320440 is an abundant number, since it is smaller than the sum of its proper divisors (16395845299640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13104042320440 is a wasteful number, since it uses less digits than its factorization.
13104042320440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 175471111 (or 175471107 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 13104042320440 its reverse (4402324040131), we get a palindrome (17506366360571).
The spelling of 13104042320440 in words is "thirteen trillion, one hundred four billion, forty-two million, three hundred twenty thousand, four hundred forty".
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