13104123320 has 16 divisors (see below), whose sum is σ = 29484277560. Its totient is φ = 5241649312.

The previous prime is 13104123317. The next prime is 13104123323. The reversal of 13104123320 is 2332140131.

It is an interprime number because it is at equal distance from previous prime (13104123317) and next prime (13104123323).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 13104123292 and 13104123301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104123323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163801502 + ... + 163801581.

Almost surely, 2^13104123320 is an apocalyptic number.

13104123320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13104123320 is an abundant number, since it is smaller than the sum of its proper divisors (16380154240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104123320 is a wasteful number, since it uses less digits than its factorization.

13104123320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 327603094 (or 327603090 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13104123320 its reverse (2332140131), we get a palindrome (15436263451).

The spelling of 13104123320 in words is "thirteen billion, one hundred four million, one hundred twenty-three thousand, three hundred twenty".