1310432522130 has 24 divisors (see below), whose sum is σ = 3407124557772. Its totient is φ = 349448672544.

The previous prime is 1310432522093. The next prime is 1310432522167. The reversal of 1310432522130 is 312252340131.

1310432522130 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 4 + 3 + 2 + 522 + 130 = 666.

It is an interprime number because it is at equal distance from previous prime (1310432522093) and next prime (1310432522167).

It can be written as a sum of positive squares in 2 ways, for example, as 1298854546929 + 11577975201 = 1139673^2 + 107601^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1310432522094 and 1310432522103.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7280180589 + ... + 7280180768.

Almost surely, 2^{1310432522130} is an apocalyptic number.

1310432522130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310432522130 is an abundant number, since it is smaller than the sum of its proper divisors (2096692035642).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310432522130 is a wasteful number, since it uses less digits than its factorization.

1310432522130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14560361370 (or 14560361367 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 27.

Adding to 1310432522130 its reverse (312252340131), we get a palindrome (1622684862261).

The spelling of 1310432522130 in words is "one trillion, three hundred ten billion, four hundred thirty-two million, five hundred twenty-two thousand, one hundred thirty".