Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …0000110101100010001101 |
3 | 1201101202120101021111011220 |
4 | 2332230113000311202031 |
5 | 3204200132304042331 |
6 | 43512014030433553 |
7 | 2521520355220410 |
oct | 276542700654215 |
9 | 51352511244156 |
10 | 13104331315341 |
11 | 41a2574442152 |
12 | 157785a0628b9 |
13 | 74096b92cc36 |
14 | 334378401b77 |
15 | 17ad18c8e296 |
hex | beb1703588d |
13104331315341 has 64 divisors (see below), whose sum is σ = 20740107632640. Its totient is φ = 7201954529280.
The previous prime is 13104331315321. The next prime is 13104331315349. The reversal of 13104331315341 is 14351313340131.
13104331315341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13104331315341 - 26 = 13104331315277 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104331315349) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 73358565 + ... + 73536981.
It is an arithmetic number, because the mean of its divisors is an integer number (324064181760).
Almost surely, 213104331315341 is an apocalyptic number.
It is an amenable number.
13104331315341 is a deficient number, since it is larger than the sum of its proper divisors (7635776317299).
13104331315341 is a wasteful number, since it uses less digits than its factorization.
13104331315341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179154.
The product of its (nonzero) digits is 19440, while the sum is 33.
Adding to 13104331315341 its reverse (14351313340131), we get a palindrome (27455644655472).
The spelling of 13104331315341 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, three hundred fifteen thousand, three hundred forty-one".
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