13104331431001 has 8 divisors (see below), whose sum is σ = 13875363671400. Its totient is φ = 12333320214528.

The previous prime is 13104331430989. The next prime is 13104331431119. The reversal of 13104331431001 is 10013413340131.

13104331431001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 2232935478601 + 10871395952400 = 1494301^2 + 3297180^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13104331431001 - 2³¹ = 13102183947353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13104338431001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3963616 + ... + 6474481.

It is an arithmetic number, because the mean of its divisors is an integer number (1734420458925).

Almost surely, 2^{13104331431001} is an apocalyptic number.

It is an amenable number.

13104331431001 is a deficient number, since it is larger than the sum of its proper divisors (771032240399).

13104331431001 is a wasteful number, since it uses less digits than its factorization.

13104331431001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10511963.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13104331431001 its reverse (10013413340131), we get a palindrome (23117744771132).

The spelling of 13104331431001 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, four hundred thirty-one thousand, one".