Base | Representation |
---|---|
bin | 11101110010111011100111… |
… | …001000110101010000011110 |
3 | 122011222121201222120110220012 |
4 | 131302323213020311100132 |
5 | 114134003214443200100 |
6 | 1142412250313523222 |
7 | 36413365610633204 |
oct | 3562734710652036 |
9 | 564877658513805 |
10 | 131043330053150 |
11 | 388331895823a9 |
12 | 128450aa113512 |
13 | 58174437a8818 |
14 | 2450761173074 |
15 | 1023b0ed34135 |
hex | 772ee723541e |
131043330053150 has 48 divisors (see below), whose sum is σ = 244798437147264. Its totient is φ = 52189860449280.
The previous prime is 131043330053137. The next prime is 131043330053227. The reversal of 131043330053150 is 51350033340131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 252697427 + ... + 253215473.
It is an arithmetic number, because the mean of its divisors is an integer number (5099967440568).
Almost surely, 2131043330053150 is an apocalyptic number.
131043330053150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131043330053150 is a deficient number, since it is larger than the sum of its proper divisors (113755107094114).
131043330053150 is a wasteful number, since it uses less digits than its factorization.
131043330053150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 540005 (or 540000 counting only the distinct ones).
The product of its (nonzero) digits is 24300, while the sum is 32.
Adding to 131043330053150 its reverse (51350033340131), we get a palindrome (182393363393281).
The spelling of 131043330053150 in words is "one hundred thirty-one trillion, forty-three billion, three hundred thirty million, fifty-three thousand, one hundred fifty".
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