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131044002101 is a prime number
BaseRepresentation
bin111101000001011010…
…1001100100100110101
3110112020200102001021022
41322002311030210311
54121334231031401
6140111211430525
712316251432155
oct1720265144465
9415220361238
10131044002101
1150636a17391
1221492455445
13c48527a05c
1464b1dcc765
15361e83771b
hex1e82d4c935

131044002101 has 2 divisors, whose sum is σ = 131044002102. Its totient is φ = 131044002100.

The previous prime is 131044002091. The next prime is 131044002109. The reversal of 131044002101 is 101200440131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123463687876 + 7580314225 = 351374^2 + 87065^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131044002101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131044002101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131044002109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522001050 + 65522001051.

It is an arithmetic number, because the mean of its divisors is an integer number (65522001051).

Almost surely, 2131044002101 is an apocalyptic number.

It is an amenable number.

131044002101 is a deficient number, since it is larger than the sum of its proper divisors (1).

131044002101 is an equidigital number, since it uses as much as digits as its factorization.

131044002101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 131044002101 its reverse (101200440131), we get a palindrome (232244442232).

The spelling of 131044002101 in words is "one hundred thirty-one billion, forty-four million, two thousand, one hundred one".