Base | Representation |
---|---|
bin | 1011111010110001111000… |
… | …1010001011011110110000 |
3 | 1201101202212201212111221010 |
4 | 2332230132022023132300 |
5 | 3204200404002030130 |
6 | 43512033552230520 |
7 | 2521523342242146 |
oct | 276543612133660 |
9 | 51352781774833 |
10 | 13104451205040 |
11 | 41a2626089048 |
12 | 157789223b440 |
13 | 74098a7188a0 |
14 | 33438a2cd596 |
15 | 17ad245720b0 |
hex | beb1e28b7b0 |
13104451205040 has 320 divisors, whose sum is σ = 47639250892800. Its totient is φ = 2950559281152.
The previous prime is 13104451205029. The next prime is 13104451205057. The reversal of 13104451205040 is 4050215440131.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 13104451204989 and 13104451205007.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2092264 + ... + 5530503.
It is an arithmetic number, because the mean of its divisors is an integer number (148872659040).
Almost surely, 213104451205040 is an apocalyptic number.
13104451205040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13104451205040 is an abundant number, since it is smaller than the sum of its proper divisors (34534799687760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13104451205040 is a wasteful number, since it uses less digits than its factorization.
13104451205040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7622844 (or 7622838 counting only the distinct ones).
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 13104451205040 its reverse (4050215440131), we get a palindrome (17154666645171).
The spelling of 13104451205040 in words is "thirteen trillion, one hundred four billion, four hundred fifty-one million, two hundred five thousand, forty".
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