Base | Representation |
---|---|
bin | 1011111010110100011001… |
… | …0101000000000011001101 |
3 | 1201101211121200222110210022 |
4 | 2332231012111000003031 |
5 | 3204203244013133240 |
6 | 43512224504551525 |
7 | 2521546134434225 |
oct | 276550625000315 |
9 | 51354550873708 |
10 | 13105125130445 |
11 | 41a2941539197 |
12 | 1577a3ba825a5 |
13 | 740a6722890a |
14 | 3344119db085 |
15 | 17ad637e39b5 |
hex | beb465400cd |
13105125130445 has 4 divisors (see below), whose sum is σ = 15726150156540. Its totient is φ = 10484100104352.
The previous prime is 13105125130429. The next prime is 13105125130483. The reversal of 13105125130445 is 54403152150131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2831324483716 + 10273800646729 = 1682654^2 + 3205277^2 .
It is a cyclic number.
It is not a de Polignac number, because 13105125130445 - 24 = 13105125130429 is a prime.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310512513040 + ... + 1310512513049.
It is an arithmetic number, because the mean of its divisors is an integer number (3931537539135).
Almost surely, 213105125130445 is an apocalyptic number.
It is an amenable number.
13105125130445 is a deficient number, since it is larger than the sum of its proper divisors (2621025026095).
13105125130445 is an equidigital number, since it uses as much as digits as its factorization.
13105125130445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2621025026094.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 13105125130445 its reverse (54403152150131), we get a palindrome (67508277280576).
The spelling of 13105125130445 in words is "thirteen trillion, one hundred five billion, one hundred twenty-five million, one hundred thirty thousand, four hundred forty-five".
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