Base | Representation |
---|---|
bin | 11000011010010001… |
… | …00101000010000111 |
3 | 1020211022211220112121 |
4 | 30031020211002013 |
5 | 203314421121120 |
6 | 10004231030411 |
7 | 642521553112 |
oct | 141510450207 |
9 | 36738756477 |
10 | 13105254535 |
11 | 561563577a |
12 | 2658b0b407 |
13 | 130b1350a9 |
14 | 8c4727579 |
15 | 51a7e35aa |
hex | 30d225087 |
13105254535 has 4 divisors (see below), whose sum is σ = 15726305448. Its totient is φ = 10484203624.
The previous prime is 13105254527. The next prime is 13105254577. The reversal of 13105254535 is 53545250131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13105254535 - 23 = 13105254527 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13105254535.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310525449 + ... + 1310525458.
It is an arithmetic number, because the mean of its divisors is an integer number (3931576362).
Almost surely, 213105254535 is an apocalyptic number.
13105254535 is a deficient number, since it is larger than the sum of its proper divisors (2621050913).
13105254535 is an equidigital number, since it uses as much as digits as its factorization.
13105254535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2621050912.
The product of its (nonzero) digits is 45000, while the sum is 34.
The spelling of 13105254535 in words is "thirteen billion, one hundred five million, two hundred fifty-four thousand, five hundred thirty-five".
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