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13105254535 = 52621050907
BaseRepresentation
bin11000011010010001…
…00101000010000111
31020211022211220112121
430031020211002013
5203314421121120
610004231030411
7642521553112
oct141510450207
936738756477
1013105254535
11561563577a
122658b0b407
13130b1350a9
148c4727579
1551a7e35aa
hex30d225087

13105254535 has 4 divisors (see below), whose sum is σ = 15726305448. Its totient is φ = 10484203624.

The previous prime is 13105254527. The next prime is 13105254577. The reversal of 13105254535 is 53545250131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13105254535 - 23 = 13105254527 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13105254535.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310525449 + ... + 1310525458.

It is an arithmetic number, because the mean of its divisors is an integer number (3931576362).

Almost surely, 213105254535 is an apocalyptic number.

13105254535 is a deficient number, since it is larger than the sum of its proper divisors (2621050913).

13105254535 is an equidigital number, since it uses as much as digits as its factorization.

13105254535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2621050912.

The product of its (nonzero) digits is 45000, while the sum is 34.

The spelling of 13105254535 in words is "thirteen billion, one hundred five million, two hundred fifty-four thousand, five hundred thirty-five".

Divisors: 1 5 2621050907 13105254535