13105330034341 has 4 divisors (see below), whose sum is σ = 13106185544800. Its totient is φ = 13104474523884.

The previous prime is 13105330034333. The next prime is 13105330034347. The reversal of 13105330034341 is 14343003350131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13105330034341 - 2³ = 13105330034333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13105330034347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 427732251 + ... + 427762888.

It is an arithmetic number, because the mean of its divisors is an integer number (3276546386200).

Almost surely, 2^{13105330034341} is an apocalyptic number.

It is an amenable number.

13105330034341 is a deficient number, since it is larger than the sum of its proper divisors (855510459).

13105330034341 is an equidigital number, since it uses as much as digits as its factorization.

13105330034341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 855510458.

The product of its (nonzero) digits is 19440, while the sum is 31.

Adding to 13105330034341 its reverse (14343003350131), we get a palindrome (27448333384472).

The spelling of 13105330034341 in words is "thirteen trillion, one hundred five billion, three hundred thirty million, thirty-four thousand, three hundred forty-one".