Base | Representation |
---|---|
bin | 1011111010110101001010… |
… | …0010101001011010100110 |
3 | 1201101212010222112200002112 |
4 | 2332231102202221122212 |
5 | 3204204203442044332 |
6 | 43512301104441022 |
7 | 2521554203204540 |
oct | 276552242513246 |
9 | 51355128480075 |
10 | 13105330034342 |
11 | 41a2a37170557 |
12 | 1577a98619172 |
13 | 740a9a80c020 |
14 | 334430cd8690 |
15 | 17ad767badb2 |
hex | beb528a96a6 |
13105330034342 has 64 divisors (see below), whose sum is σ = 25619554364544. Its totient is φ = 4879192965120.
The previous prime is 13105330034333. The next prime is 13105330034347. The reversal of 13105330034342 is 24343003350131.
It is a junction number, because it is equal to n+sod(n) for n = 13105330034299 and 13105330034308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13105330034347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 43639742 + ... + 43939022.
It is an arithmetic number, because the mean of its divisors is an integer number (400305536946).
Almost surely, 213105330034342 is an apocalyptic number.
13105330034342 is a deficient number, since it is larger than the sum of its proper divisors (12514224330202).
13105330034342 is a wasteful number, since it uses less digits than its factorization.
13105330034342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 313473.
The product of its (nonzero) digits is 38880, while the sum is 32.
Adding to 13105330034342 its reverse (24343003350131), we get a palindrome (37448333384473).
The spelling of 13105330034342 in words is "thirteen trillion, one hundred five billion, three hundred thirty million, thirty-four thousand, three hundred forty-two".
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