Search a number
-
+
13105405534145 = 52324954784701
BaseRepresentation
bin1011111010110101011100…
…0010101001111111000001
31201101212100020121110100112
42332231113002221333001
53204204332304043040
643512312403001105
72521556111015561
oct276552702517701
951355306543315
1013105405534145
1141a2a75848691
121577ab9969195
13740ab0354c72
1433443ad4cda1
1517ad7d231365
hexbeb570a9fc1

13105405534145 has 12 divisors (see below), whose sum is σ = 16439975641236. Its totient is φ = 10028484232800.

The previous prime is 13105405534103. The next prime is 13105405534157. The reversal of 13105405534145 is 54143550450131.

It can be written as a sum of positive squares in 2 ways, for example, as 3133508909584 + 9971896624561 = 1770172^2 + 3157831^2 .

It is not a de Polignac number, because 13105405534145 - 28 = 13105405533889 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2477389706 + ... + 2477394995.

It is an arithmetic number, because the mean of its divisors is an integer number (1369997970103).

Almost surely, 213105405534145 is an apocalyptic number.

It is an amenable number.

13105405534145 is a deficient number, since it is larger than the sum of its proper divisors (3334570107091).

13105405534145 is an equidigital number, since it uses as much as digits as its factorization.

13105405534145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4954784752 (or 4954784729 counting only the distinct ones).

The product of its (nonzero) digits is 360000, while the sum is 41.

Adding to 13105405534145 its reverse (54143550450131), we get a palindrome (67248955984276).

The spelling of 13105405534145 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred thirty-four thousand, one hundred forty-five".

Divisors: 1 5 23 115 529 2645 4954784701 24773923505 113960048123 569800240615 2621081106829 13105405534145