Base | Representation |
---|---|
bin | 1011111010110101011100… |
… | …0010101001111111000001 |
3 | 1201101212100020121110100112 |
4 | 2332231113002221333001 |
5 | 3204204332304043040 |
6 | 43512312403001105 |
7 | 2521556111015561 |
oct | 276552702517701 |
9 | 51355306543315 |
10 | 13105405534145 |
11 | 41a2a75848691 |
12 | 1577ab9969195 |
13 | 740ab0354c72 |
14 | 33443ad4cda1 |
15 | 17ad7d231365 |
hex | beb570a9fc1 |
13105405534145 has 12 divisors (see below), whose sum is σ = 16439975641236. Its totient is φ = 10028484232800.
The previous prime is 13105405534103. The next prime is 13105405534157. The reversal of 13105405534145 is 54143550450131.
It can be written as a sum of positive squares in 2 ways, for example, as 3133508909584 + 9971896624561 = 1770172^2 + 3157831^2 .
It is not a de Polignac number, because 13105405534145 - 28 = 13105405533889 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2477389706 + ... + 2477394995.
It is an arithmetic number, because the mean of its divisors is an integer number (1369997970103).
Almost surely, 213105405534145 is an apocalyptic number.
It is an amenable number.
13105405534145 is a deficient number, since it is larger than the sum of its proper divisors (3334570107091).
13105405534145 is an equidigital number, since it uses as much as digits as its factorization.
13105405534145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4954784752 (or 4954784729 counting only the distinct ones).
The product of its (nonzero) digits is 360000, while the sum is 41.
Adding to 13105405534145 its reverse (54143550450131), we get a palindrome (67248955984276).
The spelling of 13105405534145 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred thirty-four thousand, one hundred forty-five".
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