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13105420330032 = 24321991600728571
BaseRepresentation
bin1011111010110101011111…
…1011000110010000110000
31201101212101021110011111100
42332231113323012100300
53204204400101030112
643512314052044400
72521556350541352
oct276552773062060
951355337404440
1013105420330032
1141a2a83133a98
121577b02903700
13740ab3435724
1433443ccc10d2
1517ad7e6a52dc
hexbeb57ec6430

13105420330032 has 120 divisors (see below), whose sum is σ = 36864874425600. Its totient is φ = 4346097655680.

The previous prime is 13105420330021. The next prime is 13105420330039. The reversal of 13105420330032 is 23003302450131.

13105420330032 is a `hidden beast` number, since 1 + 310 + 5 + 42 + 0 + 3 + 300 + 3 + 2 = 666.

It is a super-2 number, since 2×131054203300322 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13105420329978 and 13105420330005.

It is not an unprimeable number, because it can be changed into a prime (13105420330039) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 458682307 + ... + 458710877.

It is an arithmetic number, because the mean of its divisors is an integer number (307207286880).

Almost surely, 213105420330032 is an apocalyptic number.

13105420330032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13105420330032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18432437212800).

13105420330032 is an abundant number, since it is smaller than the sum of its proper divisors (23759454095568).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13105420330032 is a wasteful number, since it uses less digits than its factorization.

13105420330032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44791 (or 44782 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 27.

Adding to 13105420330032 its reverse (23003302450131), we get a palindrome (36108722780163).

The spelling of 13105420330032 in words is "thirteen trillion, one hundred five billion, four hundred twenty million, three hundred thirty thousand, thirty-two".

Divisors: 1 2 3 4 6 8 9 12 16 18 24 36 48 72 144 199 398 597 796 1194 1592 1791 2388 3184 3582 4776 7164 9552 14328 16007 28571 28656 32014 48021 57142 64028 85713 96042 114284 128056 144063 171426 192084 228568 256112 257139 288126 342852 384168 457136 514278 576252 685704 768336 1028556 1152504 1371408 2057112 2305008 3185393 4114224 5685629 6370786 9556179 11371258 12741572 17056887 19112358 22742516 25483144 28668537 34113774 38224716 45485032 50966288 51170661 57337074 68227548 76449432 90970064 102341322 114674148 136455096 152898864 204682644 229348296 272910192 409365288 457335997 458696592 818730576 914671994 1372007991 1829343988 2744015982 3658687976 4116023973 5488031964 7317375952 8232047946 10976063928 16464095892 21952127856 32928191784 65856383568 91009863403 182019726806 273029590209 364039453612 546059180418 728078907224 819088770627 1092118360836 1456157814448 1638177541254 2184236721672 3276355082508 4368473443344 6552710165016 13105420330032