13105443221541 has 32 divisors (see below), whose sum is σ = 21190086311040. Its totient is φ = 7939103356800.

The previous prime is 13105443221539. The next prime is 13105443221551. The reversal of 13105443221541 is 14512234450131.

13105443221541 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 5 + 4 + 432 + 215 + 4 + 1 = 666.

13105443221541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13105443221541 - 2¹ = 13105443221539 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13105443221496 and 13105443221505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13105443221551) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9312480 + ... + 10627001.

It is an arithmetic number, because the mean of its divisors is an integer number (662190197220).

Almost surely, 2^{13105443221541} is an apocalyptic number.

13105443221541 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13105443221541 is a deficient number, since it is larger than the sum of its proper divisors (8084643089499).

13105443221541 is a wasteful number, since it uses less digits than its factorization.

13105443221541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19941714 (or 19941708 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 36.

Adding to 13105443221541 its reverse (14512234450131), we get a palindrome (27617677671672).

The spelling of 13105443221541 in words is "thirteen trillion, one hundred five billion, four hundred forty-three million, two hundred twenty-one thousand, five hundred forty-one".