Base | Representation |
---|---|
bin | 11101110011110000100000… |
… | …001001001100001000011000 |
3 | 122012012001022211210122211220 |
4 | 131303300200021030020120 |
5 | 114140421021440214000 |
6 | 1142454321505252040 |
7 | 36420446133130653 |
oct | 3563604011141030 |
9 | 565161284718756 |
10 | 131100121023000 |
11 | 388552815a9628 |
12 | 128540b9334020 |
13 | 581c8c4454bac |
14 | 24533cb76a89a |
15 | 10253359a31a0 |
hex | 773c2024c218 |
131100121023000 has 256 divisors, whose sum is σ = 412524623347200. Its totient is φ = 34662574425600.
The previous prime is 131100121022963. The next prime is 131100121023007. The reversal of 131100121023000 is 320121001131.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131100121023007) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 204571074 + ... + 205210926.
It is an arithmetic number, because the mean of its divisors is an integer number (1611424309950).
Almost surely, 2131100121023000 is an apocalyptic number.
131100121023000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131100121023000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (206262311673600).
131100121023000 is an abundant number, since it is smaller than the sum of its proper divisors (281424502324200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131100121023000 is a wasteful number, since it uses less digits than its factorization.
131100121023000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 640459 (or 640445 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 131100121023000 its reverse (320121001131), we get a palindrome (131420242024131).
The spelling of 131100121023000 in words is "one hundred thirty-one trillion, one hundred billion, one hundred twenty-one million, twenty-three thousand".
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