131100240402311 has 4 divisors (see below), whose sum is σ = 134643490142952. Its totient is φ = 127556990661672.

The previous prime is 131100240402289. The next prime is 131100240402389. The reversal of 131100240402311 is 113204042001131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131100240402311 - 2²⁶ = 131100173293447 is a prime.

It is a super-2 number, since 2×131100240402311² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131100240402011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1771624870265 + ... + 1771624870338.

It is an arithmetic number, because the mean of its divisors is an integer number (33660872535738).

Almost surely, 2^{131100240402311} is an apocalyptic number.

131100240402311 is a deficient number, since it is larger than the sum of its proper divisors (3543249740641).

131100240402311 is an equidigital number, since it uses as much as digits as its factorization.

131100240402311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3543249740640.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 131100240402311 its reverse (113204042001131), we get a palindrome (244304282403442).

The spelling of 131100240402311 in words is "one hundred thirty-one trillion, one hundred billion, two hundred forty million, four hundred two thousand, three hundred eleven".